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2x^2-110x=-1500
We move all terms to the left:
2x^2-110x-(-1500)=0
We add all the numbers together, and all the variables
2x^2-110x+1500=0
a = 2; b = -110; c = +1500;
Δ = b2-4ac
Δ = -1102-4·2·1500
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-110)-10}{2*2}=\frac{100}{4} =25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-110)+10}{2*2}=\frac{120}{4} =30 $
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